Re: Why does sucrose, a double sugar, dissolve more easily than glucose?

I will assume that they do have different solubilities and that the 
solubility of sucrose (glucose plus fructose) is greater than that of 
glucose alone.  I have to say that I am not sure what the answer here is, 
but if I had to guess I would guess that it is a question of the entropy of 
the water solution in which they exist.  Specifically, water has a 
relatively ordered hydrogen-bonding structure in which all hydrogen bond 
donors and acceptors are satisfied in the sense that they are partnered 
with their complement.  When something is dissolved in water it disrupts 
this hydrogen-bonding network since the water molecules around the thing 
dissolved can't hydrogen bond to it and instead cluster around.  This 
lowers their entropy and therefore destabilizes the overall system.  When 
glucose and fructose are dimerized into sucrose, a part of each of their 
surfaces are against each other and thus water isn't next to it.  Thus 
there is less surface area when the two molecules are dimerized for water 
to pack against, so less water packs against it, so less water has its 
entropy lowered, so the destabilization of the system is less, and so it 
dissolves more.