| MadSci Network: Earth Sciences | 
Some of the answer you seek probably has to do with how accurate you want to be. I can not find a highly accurate empirical equation that will account for the actual pressure profile of the atmosphere.
I can, however, get you about half way there...
If we model the earth's atmosphere as an ideal gas, then the pressure at any height Y (expressed in kilometers) is
        P = Po * e(-AY)   
 
        where Po is sea level atmospheric pressure
        A is 0.116 per km
                        (see Resnick and Halliday, "Physics" Part 1, pg. 360).
Now there *must* somewhere be an equation, probably a polynomial curve fit
to experimental data, for the vapor pressure of water vs. temperature. 
There is extremely accurate data on this (see the 
Handbook of Chemistry and Physics). My ancient 
edition has a very complete table of this, and I'm
reasonably sure that more recent editions do as well).  But I can't find
an equation fitted to this kind of data, even after looking into a book on 
atmospheric modelling.
If one could find such an equation, then it will probably have the form of
	VP(T) =  C + DT + ET2 + FT3     
        where C, D, E, F are constants
        T is the temperature
        VP(T) is the vapor pressure
Now, boiling occurs when the vapor pressure equals atmospheric, so that
the "final answer" is
    C + DT + ET2 + FT3 = Po * e(-AY)
Now all we need are C, D, E, and F :-)
To complete your quest for a single equation, I can think of two ways to continue:
Try the links in the MadSci Library for more information on Earth Sciences.