MadSci Network: Physics
Query:

Re: What is the mechanism for the decay of the charged pion?

Date: Wed Feb 28 20:48:54 2007
Posted By: Randall Scalise, Faculty, Physics
Area of science: Physics
ID: 1171745250.Ph
Message:

To whom it concerns,

Everything that you wrote is essentially correct.  The charged pion
does indeed decay through the weak interaction with a relatively
long mean lifetime of 2.6E-8 seconds compared to the neutral pion
which decays electromagnatically with the much shorter lifetime of
only 8.4E-17 seconds.  This is like comparing 10 years to 1 second!
I discussed this difference in a previous post.
 http://www.madsci.org/posts/archives/2001-05/989934620.Ph.r.html

Most of the time (99.98770%) the decay products are a muon and a muon
antineutrino (for the negative pion) or an antimuon and a muon
neutrino (for the positive pion).  The virtual particle which mediates
the decay to first order in perturbation theory is the W boson, the
carrier of the weak force.  The pion is a spin-zero particle while the
W boson is a spin-one particle.  All true.

The confusion seems to be the way in which angular momentum is
conserved from the initial zero angular momentum pion state to the
intermediate virtual spin-one W boson state.  A massive spin-one
particle like the W boson has three possible spin states which you can
think of as "up", "zero", and "down".  The rules of quantum mechanics
restrict the angular momentum to values from maximum (+1) to minimum
(-1) separated by one unit, and zero is one of the allowed values.  A
W boson in the "zero" spin state will behave like a spinless particle.
In the jargon, these are called longitudinally polarized W bosons.

The pion lifetimes and branching ratios came from
The Particle Data Group  http://pdg.lbl.gov/2006/tables/mxxx.pdf


--Dr. Randall J. Scalise    http://www.phys.psu.edu/~scalise/




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